Post by 《§》carbonara <3〖ƧƐ〗 on Aug 21, 2015 14:08:03 GMT
Let |S| be the cardinality of the set S
Let A_k be the kth aleph number (see wikipedia if you don't know what it is)
Knowing that |R| = 2^|N| ("the cardinality of the set of all real numbers is the cardinality of the set of all subsets of the set of all natural numbers"), that |S*K| = |S| * |K| for any sets S and K, that |N| = A_0 and that A_0 * 2 = A_0 (cardinal arithmetic), prove that |C| = |R| (C is the set of all complex numbers)
So easyyyyy I did it in a minute xD
Let A_k be the kth aleph number (see wikipedia if you don't know what it is)
Knowing that |R| = 2^|N| ("the cardinality of the set of all real numbers is the cardinality of the set of all subsets of the set of all natural numbers"), that |S*K| = |S| * |K| for any sets S and K, that |N| = A_0 and that A_0 * 2 = A_0 (cardinal arithmetic), prove that |C| = |R| (C is the set of all complex numbers)
So easyyyyy I did it in a minute xD
